3x^2+14x+12x=4

Solution for 3x^2+14x+12x=4 equation:

3x^2+14x+12x=4

We move all terms to the left:

3x^2+14x+12x-(4)=0

We add all the numbers together, and all the variables

3x^2+26x-4=0

a = 3; b = 26; c = -4;
Δ = b2-4ac
Δ = 262-4·3·(-4)
Δ = 724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{724}=\sqrt{4*181}=\sqrt{4}*\sqrt{181}=2\sqrt{181}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{181}}{2*3}=\frac{-26-2\sqrt{181}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{181}}{2*3}=\frac{-26+2\sqrt{181}}{6}
$